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In the original (d4) game you can win by throwing a 5th time and getting no 1's (ie. 15 consecutive d4 results of 2, 3 or 4). There is a 1.3% (1 in 75) chance of being able to do this. To play this game using d6s and have the same probability of winning in style you should win by throwing (1 then 2 then 3 then 4 then 5 then) 6 dice (which you could do theoretically in 2.2% of attempts). This is a correction to the file above. Technically you'd have to throw 2 more without 1's to hit nearly the same odds (1.5%) but if you've just thrown 21 d6 and had no 1's I figure that ought to be enough to win you the game
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- Edited Wed Feb 18, 2009 1:24 pm
Posted Tue Feb 17, 2009 2:40 pm
